Use the image to answer the question.

A coordinate plane's axes range from negative 10 to 10 by 1-unit increments. Two rays are plotted. The first ray starts from a closed endpoint, while the second ray starts from an open endpoint.

Determine the graph's correct piecewise function.

Option #1: f(x)={2x+1, x>1−x+3, x<1


Option #2: f(x)={2x+1, x>1−x+3, x≤1


Option #3: f(x)={−2x+1, x>1x+3, x≤1


(1 point)
Option #
is the graph's correct piecewise function.

1 answer

To determine which option represents the graph's correct piecewise function, let's analyze the features of the rays as described.

From your description:

  • The first ray starts from a closed endpoint, suggesting it should be included in the function for that endpoint (i.e., use ≥ or ≤).
  • The second ray starts from an open endpoint, indicating that this endpoint should not be included (i.e., use > or <).

Given this information, we can interpret the provided options:

  1. Option #1: \( f(x) = \begin{cases} 2x + 1 & x > 1 \ -x + 3 & x < 1 \end{cases} \)

    • This option uses > for the first branch, which is incorrect because the ray starts from a closed endpoint.
  2. Option #2: \( f(x) = \begin{cases} 2x + 1 & x > 1 \ -x + 3 & x \leq 1 \end{cases} \)

    • This option correctly uses ≥ for the second branch, indicating that the closed endpoint is included in this piece of the function.
  3. Option #3: \( f(x) = \begin{cases} -2x + 1 & x > 1 \ x + 3 & x \leq 1 \end{cases} \)

    • This option does not match the equations provided and also switches the rays.

Based on the requirement that the function includes the closed endpoint at \( x = 1 \) and the open endpoint for \( x > 1 \), Option #2 is the correct piecewise function.

So, the answer is: Option #2.

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