Use the image to answer the question.

A coordinate plane with four quadrants showsthe x-axis ranging from negative 4 to 12 in increments of 1 and the y-axis from 1 to negative 16 in increments of 1. Points upper A, upper B, upper A prime, and upper B prime are plotted on quadrant 4. The plotted points are as follows: Upper A is left parenthesis 1 comma negative 3 right parenthesis and upper B is left parenthesis 2 comma negative 4 right parenthesis. The points are joined by a line. Upper A prime is plotted as left parenthesis 4 comma negative 12 right parenthesis and upper B prime as left parenthesis 8 comma negative 16 right parenthesis. The points are joined by a line.

Determine the scale factor used in the dilation of line segment AB
, centered at the origin.

(1 point)
Responses

−4
negative 4

14
Start Fraction 1 over 4 End Fraction

2
2

4
4
Skip to navigation

1 answer

To determine the scale factor used in the dilation of line segment AB, we first need to identify the coordinates of points A and B and their corresponding points A' and B' after dilation.

The points are:

  • A (1, -3)
  • B (2, -4)
  • A' (4, -12)
  • B' (8, -16)

The scale factor (k) for a dilation centered at the origin can be calculated using the formula:

\[ k = \frac{\text{distance from origin to A'}}{\text{distance from origin to A}} \]

First, we calculate the distances from the origin to each point. The distance from the origin to a point \( (x, y) \) is given by the formula:

\[ d = \sqrt{x^2 + y^2} \]

Calculating the distance from the origin to point A: \[ d_A = \sqrt{1^2 + (-3)^2} = \sqrt{1 + 9} = \sqrt{10} \]

Calculating the distance from the origin to point A': \[ d_{A'} = \sqrt{4^2 + (-12)^2} = \sqrt{16 + 144} = \sqrt{160} \]

Now, we compute the scale factor k: \[ k = \frac{d_{A'}}{d_A} = \frac{\sqrt{160}}{\sqrt{10}} = \sqrt{\frac{160}{10}} = \sqrt{16} = 4 \]

Therefore, the scale factor used in the dilation of line segment AB, centered at the origin, is 4.