To analyze the transformations between the triangles ABC and A″B″C″, we note the following:
- Triangle ABC has vertices at A(-4, 5), B(-1, 3), and C(-3, 1).
- Triangle A″B″C″ has vertices at A"(1, 0), B"(-2, -2), and C"(0, -4).
To go from triangle ABC to triangle A″B″C″, we can look at the transformations step by step:
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The first step could involve reflecting triangle ABC across the y-axis, which would take A(-4, 5) to A' (4, 5), B (-1, 3) to B' (1, 3), and C (-3, 1) to C' (3, 1).
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The second transformation would involve translating this reflected triangle A'B'C' downwards by moving all points down by 5 units and left by 3 units:
- A' (4, 5) → (4 - 3, 5 - 5) = (1, 0)
- B' (1, 3) → (1 - 3, 3 - 5) = (-2, -2)
- C' (3, 1) → (3 - 3, 1 - 5) = (0, -4)
The key here is to determine that the first step was a reflection across the y-axis, and the second step was a translation.
For triangle A'B'C' and A″B″C″, they do share the same orientation since both triangles have been reflected and translated appropriately.
Therefore, the transformations resulting in the congruence of triangle ABC with triangle A″B″C″ can be described as:
Reflection across the y-axis and then a translation of (-3, -5) shows that triangle ABC is congruent to triangle A″B″C″.
Thus, the correct response is: Reflection across the y-axis and then a translation of (-3, -5) shows that triangle ABC is congruent to triangle A″B″C″.