To find the third vertex of the triangle, we can use the properties of the median and the midpoint of the opposite side.
We have two vertices of the triangle: \( A(2, 5) \) and \( B(5, 9) \), and the median from vertex \( A \) ends at the point \( M(6.5, 6.5) \). The point \( M \) is the midpoint of the line segment connecting the third vertex \( C \) and the midpoint of \( AB \).
First, we calculate the midpoint \( D \) of the segment \( AB \): \[ D = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right) = \left( \frac{2 + 5}{2}, \frac{5 + 9}{2} \right) = \left( \frac{7}{2}, 7 \right) = (3.5, 7) \]
Next, since \( M \) is the midpoint of segment \( AC \), we can set up the midpoint formula for point \( M \): \[ M = \left( \frac{x_A + x_C}{2}, \frac{y_A + y_C}{2} \right) \] Substituting \( A(2, 5) \) and \( M(6.5, 6.5) \): \[ (6.5, 6.5) = \left( \frac{2 + x_C}{2}, \frac{5 + y_C}{2} \right) \]
From this, we can create two equations:
- \( 6.5 = \frac{2 + x_C}{2} \)
- \( 6.5 = \frac{5 + y_C}{2} \)
Now, solving for \( x_C \) and \( y_C \):
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For \( x_C \): \[ 6.5 \cdot 2 = 2 + x_C \ 13 = 2 + x_C \ x_C = 13 - 2 \ x_C = 11 \]
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For \( y_C \): \[ 6.5 \cdot 2 = 5 + y_C \ 13 = 5 + y_C \ y_C = 13 - 5 \ y_C = 8 \]
Thus, the coordinates of the third vertex \( C \) are \( (11, 8) \).
However, none of the responses list the correct point \( (11, 8) \). Let's review the given options to find the best match:
- \( (8, 4) \)
- \( (5.8, 7.8) \)
- \( (6.5, 6.5) \)
- \( (4, 8) \)
Among the provided options, \( (4, 8) \) is the closest possible point when considering geometric positions and median properties, but it still does not match the calculated position.
Conclusively, based on the information and calculations provided, none of the listed points accurately represents the third vertex of the triangle. The third vertex should be at \( (11, 8) \).