Use the image to answer the question.

A coordinate plane shows an upward-opening parabola with a plotted point. Both axes range from negative 20 to 20 in increments of 5.

What is the vertex form of the graphed equation?

(1 point)
y=
(x−
)2+
Remaining Attempts : 3
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1 answer

To determine the vertex form of a parabola, we use the equation:

\[ y = a(x - h)^2 + k \]

where \((h, k)\) is the vertex of the parabola.

From your description, it seems that the parabola is opening upward, meaning \(a > 0\). The vertex of the parabola is crucial for identifying the values of \(h\) and \(k\).

Since I don’t have visibility to the image you mentioned, you will need to identify the coordinates of the vertex from the graph.

  1. Identify the vertex - Look for the point where the parabola reaches its minimum (which is the vertex for an upward-opening parabola). This point will have coordinates \((h, k)\).

  2. Fill in the values - Once you’ve identified \((h, k)\), substitute these values into the vertex form equation:

    \[ y = a(x - h)^2 + k \]

    To find \(a\), you can use another point on the parabola that is plotted to find how "wide" or "narrow" the parabola is.

  3. Complete the equation - If you gather the vertex coordinates \((h, k)\) and the value of \(a\):

    \[ y = a(x - [h])^2 + [k] \]

Thus, without having the specific coordinates from the image, I suggest using these steps to find your equation. If you can provide the vertex coordinates or any other point on the parabola, I can help you write the specific vertex form equation!