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A coordinate plane ranges from negative 9 to 9 in unit increments on the x-axis and from 11 to negative 11 in unit increments on the y-axis. A line with arrows at both the ends joins two plotted points and extends beyond. The coordinates of the plotted points are: left parenthesis 0 comma 0 right parenthesis and left parenthesis 5 comma 1 right parenthesis.

Is this the correct graph of the equation y=15x ?

(1 point)
Responses

No, it is not the correct graph because the slope m=riserun=15.
No, it is not the correct graph because the slope m equals Start Fraction rise over run End Fraction equals Start Fraction 1 over 5 End Fraction .

Yes, it is the correct graph because the ordered pair (0, 0) satisfies the equation and the slope m=riserun=15.
Yes, it is the correct graph because the ordered pair left parenthesis 0 comma 0 right parenthesis satisfies the equation and the slope m equals Start Fraction rise over run End Fraction equals Start Fraction 1 over 5 End Fraction .

Yes, it is the correct graph because the slope =51.
Yes, it is the correct graph because the slope equals Start Fraction 5 over 1 End Fraction .

No, it is not the correct graph because the ordered pair (1, 5) is not a point on the graph of y=15x
No, it is not the correct graph because the ordered pair left parenthesis 1 comma 5 right parenthesis is not a point on the graph of y equals Start Fraction 1 over 5 End Fraction x
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PreviousReview

1 answer

To determine whether the graph represents the equation \( y = 15x \), we need to consider two pieces of information: the coordinates of the plotted points and the slope of the line connecting them.

  1. Coordinates of the plotted points: (0, 0) and (5, 1).

  2. Calculate the slope \( m \) using the formula \( m = \frac{\text{rise}}{\text{run}} \):

    • From (0, 0) to (5, 1), the rise is \( 1 - 0 = 1 \) and the run is \( 5 - 0 = 5 \).
    • Therefore, the slope \( m = \frac{1}{5} \).

  3. Comparison with the given equation: The equation \( y = 15x \) has a slope of 15.

Since the calculated slope \( \frac{1}{5} \) does not match the slope of the line \( y = 15x \), we can conclude that this is not the correct graph of the equation.

The correct response is: No, it is not the correct graph because the slope m equals \( \frac{1}{5} \).