To determine which point represents the solution to the system of linear equations \(y = 3x + 1\) and \(y = -2x - 4\), we need to check which of the given points satisfies both equations.
Let's evaluate each point:
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For (0, 1):
- Plugging \(x = 0\) into \(y = 3x + 1\): \(y = 3(0) + 1 = 1\) (True)
- Plugging \(x = 0\) into \(y = -2x - 4\): \(y = -2(0) - 4 = -4\) (False) This point is NOT a solution.
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For (-2, 3):
- Plugging \(x = -2\) into \(y = 3x + 1\): \(y = 3(-2) + 1 = -6 + 1 = -5\) (False)
- Plugging \(x = -2\) into \(y = -2x - 4\): \(y = -2(-2) - 4 = 4 - 4 = 0\) (False) This point is NOT a solution.
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For (-1, -2):
- Plugging \(x = -1\) into \(y = 3x + 1\): \(y = 3(-1) + 1 = -3 + 1 = -2\) (True)
- Plugging \(x = -1\) into \(y = -2x - 4\): \(y = -2(-1) - 4 = 2 - 4 = -2\) (True) This point IS a solution.
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For (0, -4):
- Plugging \(x = 0\) into \(y = 3x + 1\): \(y = 3(0) + 1 = 1\) (False)
- Plugging \(x = 0\) into \(y = -2x - 4\): \(y = -2(0) - 4 = -4\) (True) This point is NOT a solution.
The point that represents the solution to the linear system is (-1, -2).