To determine which of the points is a solution to the system of equations given by \( y = 2x + 5 \) and \( y = -x \), we will substitute each point into both equations.
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Point (0, 5):
- For \( y = 2x + 5 \): \[ 5 = 2(0) + 5 \implies 5 = 5 \quad \text{(True)} \]
- For \( y = -x \): \[ 5 = -(0) \implies 5 = 0 \quad \text{(False)} \] This point is not a solution to the system.
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Point (2, 3):
- For \( y = 2x + 5 \): \[ 3 = 2(2) + 5 \implies 3 = 4 + 5 \implies 3 = 9 \quad \text{(False)} \] This point is not a solution to the system.
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Point (1, -1):
- For \( y = 2x + 5 \): \[ -1 = 2(1) + 5 \implies -1 = 2 + 5 \implies -1 = 7 \quad \text{(False)} \] This point is not a solution to the system.
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Point (-3, 3):
- For \( y = 2x + 5 \): \[ 3 = 2(-3) + 5 \implies 3 = -6 + 5 \implies 3 = -1 \quad \text{(False)} \] This point is not a solution to the system.
None of the provided points (0,5), (2,3), (1,-1), or (-3,3) satisfy both equations. Therefore, none of the points is a solution to the system.