Question
Use the image to answer the question.
A coordinate graph goes from negative 10 to 10 in 1-unit increments on both the x- and y-axes. Two linear equations are graphed, along with two points.
The image shows the graph of the system of linear equations {y=2x+2y=2x−4
. Which of the following points, if any, are solutions to the system of equations?
(1 point)
Responses
(0,−4)
open paren 0 comma negative 4 close paren
Neither of these points are solutions.
Neither of these points are solutions.
(0,2)
open paren 0 comma 2 close paren
Both of these points are solutions.
A coordinate graph goes from negative 10 to 10 in 1-unit increments on both the x- and y-axes. Two linear equations are graphed, along with two points.
The image shows the graph of the system of linear equations {y=2x+2y=2x−4
. Which of the following points, if any, are solutions to the system of equations?
(1 point)
Responses
(0,−4)
open paren 0 comma negative 4 close paren
Neither of these points are solutions.
Neither of these points are solutions.
(0,2)
open paren 0 comma 2 close paren
Both of these points are solutions.
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To determine if the points \( (0, -4) \) and \( (0, 2) \) are solutions to the system of equations given by \( y = 2x + 2 \) and \( y = 2x - 4 \), we can substitute the x-coordinate of each point into the equations and see if the corresponding y-coordinate matches.
1. **For the point \( (0, -4) \)**:
- Substitute \( x = 0 \) into the first equation:
\[
y = 2(0) + 2 = 2
\]
This does not match \( -4 \).
- Substitute \( x = 0 \) into the second equation:
\[
y = 2(0) - 4 = -4
\]
This matches \( -4 \).
- Therefore, \( (0, -4) \) is a solution to the second equation but not to the first.
2. **For the point \( (0, 2) \)**:
- Substitute \( x = 0 \) into the first equation:
\[
y = 2(0) + 2 = 2
\]
This matches \( 2 \).
- Substitute \( x = 0 \) into the second equation:
\[
y = 2(0) - 4 = -4
\]
This does not match \( 2 \).
- Therefore, \( (0, 2) \) is a solution to the first equation but not to the second.
Since neither point is a solution to both equations of the system, the correct response is:
**Neither of these points are solutions.**
1. **For the point \( (0, -4) \)**:
- Substitute \( x = 0 \) into the first equation:
\[
y = 2(0) + 2 = 2
\]
This does not match \( -4 \).
- Substitute \( x = 0 \) into the second equation:
\[
y = 2(0) - 4 = -4
\]
This matches \( -4 \).
- Therefore, \( (0, -4) \) is a solution to the second equation but not to the first.
2. **For the point \( (0, 2) \)**:
- Substitute \( x = 0 \) into the first equation:
\[
y = 2(0) + 2 = 2
\]
This matches \( 2 \).
- Substitute \( x = 0 \) into the second equation:
\[
y = 2(0) - 4 = -4
\]
This does not match \( 2 \).
- Therefore, \( (0, 2) \) is a solution to the first equation but not to the second.
Since neither point is a solution to both equations of the system, the correct response is:
**Neither of these points are solutions.**
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