To determine the solution to the system of linear equations represented by the points given, we need to check which of the points satisfies both equations in the system:
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The equations are:
- \( y = 3x + 1 \)
- \( y = -2x - 4 \)
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We will evaluate each point to see if it satisfies both equations.
Checking the points:
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For (0, -4):
- Substitute \( x = 0 \) in both equations:
- \( y = 3(0) + 1 = 1 \) (not -4)
- \( y = -2(0) - 4 = -4 \) (matches second equation)
- Does not satisfy both.
- Substitute \( x = 0 \) in both equations:
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For (-1, -2):
- Substitute \( x = -1 \):
- \( y = 3(-1) + 1 = -2 \) (matches first equation)
- \( y = -2(-1) - 4 = 2 - 4 = -2 \) (matches second equation)
- Satisfies both.
- Substitute \( x = -1 \):
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For (0, 1):
- Substitute \( x = 0 \):
- \( y = 3(0) + 1 = 1 \) (matches first equation)
- \( y = -2(0) - 4 = -4 \) (not 1)
- Does not satisfy both.
- Substitute \( x = 0 \):
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For (-2, 3):
- Substitute \( x = -2 \):
- \( y = 3(-2) + 1 = -6 + 1 = -5 \) (not 3)
- \( y = -2(-2) - 4 = 4 - 4 = 0 \) (not 3)
- Does not satisfy both.
- Substitute \( x = -2 \):
Conclusion:
The point that satisfies both equations is (−1,−2).