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Use the image to answer the question. A Cartesian coordinate plane's axes range from negative 4 to 4, both by 1-unit increments...Question
Use the image to answer the question.
A Cartesian coordinate plane's axes range from negative 4 to 4, both by 1-unit increments. 2 dotted lines with arrows at both ends are plotted, and various regions of the graph are marked.
Which of the descriptions is true about the graph of the system of inequalities?
Option #1: no solutions
Option #2: one solution
Option #3: infinite solutions
A Cartesian coordinate plane's axes range from negative 4 to 4, both by 1-unit increments. 2 dotted lines with arrows at both ends are plotted, and various regions of the graph are marked.
Which of the descriptions is true about the graph of the system of inequalities?
Option #1: no solutions
Option #2: one solution
Option #3: infinite solutions
Answers
Answer
the equatipons are
y > 3x + 2
y < 3x - 3
y > 3x + 2
y < 3x - 3
Answered by
GPT-4o mini
Without being able to see the image, I can only provide guidance based on typical scenarios involving systems of inequalities.
1. **No Solutions**: This occurs when the inequalities contradict each other to the point that there are no overlapping regions on the graph.
2. **One Solution**: This happens if the inequalities intersect at exactly one point. This situation is quite rare for systems of inequalities as most typically cover a region rather than a single point.
3. **Infinite Solutions**: This situation arises when the inequalities define a common region that contains many possible points. For example, if the inequalities create overlapping regions in a certain area, or if they are equivalent (one inequality is derived from another), there would be infinite solutions.
If you can provide more details about the specific arrangements of the lines and the shaded regions in the graph, I could help determine which option is correct more accurately.
1. **No Solutions**: This occurs when the inequalities contradict each other to the point that there are no overlapping regions on the graph.
2. **One Solution**: This happens if the inequalities intersect at exactly one point. This situation is quite rare for systems of inequalities as most typically cover a region rather than a single point.
3. **Infinite Solutions**: This situation arises when the inequalities define a common region that contains many possible points. For example, if the inequalities create overlapping regions in a certain area, or if they are equivalent (one inequality is derived from another), there would be infinite solutions.
If you can provide more details about the specific arrangements of the lines and the shaded regions in the graph, I could help determine which option is correct more accurately.
Answered by
GPT-4o mini
Given the inequalities \( y > 3x + 2 \) and \( y < 3x - 3 \), we can analyze them to determine the nature of the solutions.
1. **Graphing the Inequalities**:
- The line for the equation \( y = 3x + 2 \) will have a slope of 3 and a y-intercept of 2. The region above this line represents the solutions to the inequality \( y > 3x + 2 \).
- The line for the equation \( y = 3x - 3 \) will also have a slope of 3, but a y-intercept of -3. The region below this line represents the solutions to the inequality \( y < 3x - 3 \).
2. **Analyzing the Inequalities**:
- Both lines have the same slope (3), which means they are parallel.
- Since one inequality is above the first line and one is below the second line, these two regions cannot overlap.
Since there is no common area where both inequalities are satisfied, **the system of inequalities does not have any solutions.**
Therefore, the correct option is:
**Option #1: no solutions.**
1. **Graphing the Inequalities**:
- The line for the equation \( y = 3x + 2 \) will have a slope of 3 and a y-intercept of 2. The region above this line represents the solutions to the inequality \( y > 3x + 2 \).
- The line for the equation \( y = 3x - 3 \) will also have a slope of 3, but a y-intercept of -3. The region below this line represents the solutions to the inequality \( y < 3x - 3 \).
2. **Analyzing the Inequalities**:
- Both lines have the same slope (3), which means they are parallel.
- Since one inequality is above the first line and one is below the second line, these two regions cannot overlap.
Since there is no common area where both inequalities are satisfied, **the system of inequalities does not have any solutions.**
Therefore, the correct option is:
**Option #1: no solutions.**
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