To determine which point is a solution to the simultaneous inequalities \( y < \frac{1}{2}x \) and \( y > \frac{1}{3}x + 3 \), let's assess each option one by one.
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For the inequality \( y < \frac{1}{2}x \):
- This line has a slope of \(\frac{1}{2}\) and y-intercept 0. Points below this line satisfy the inequality.
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For the inequality \( y > \frac{1}{3}x + 3 \):
- This line has a slope of \(\frac{1}{3}\) and y-intercept 3. Points above this line satisfy the inequality.
Now, let's evaluate each point:
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(25,12):
- \( y < \frac{1}{2}(25) = 12.5 \) → \( 12 < 12.5 \) (True)
- \( y > \frac{1}{3}(25) + 3 = \frac{25}{3} + 3 \approx 8.33 + 3 = 11.33 \) → \( 12 > 11.33 \) (True)
- This point satisfies both inequalities.
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(3,6):
- \( y < \frac{1}{2}(3) = 1.5 \) → \( 6 < 1.5 \) (False)
- This point does not satisfy the first inequality.
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(2,2):
- \( y < \frac{1}{2}(2) = 1 \) → \( 2 < 1 \) (False)
- This point does not satisfy the first inequality.
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(10,5):
- \( y < \frac{1}{2}(10) = 5 \) → \( 5 < 5 \) (False)
- This point does not satisfy the first inequality.
Given this analysis, the only point that satisfies both inequalities is:
(25,12)