To determine the percentage of students who have dogs as pets: 10 dogs / 23 total students = 43.5%
To determine the percentage of students who have hamsters as pets: 3 hamsters / 23 total students = 13%
The difference in percentages is: 43.5% - 13% = 30.5%
Rounded to the tenths place, the correct answer is 30.5%, which is closest to option A: The difference in the percentage of students who have dogs for pets and the percentage of students who have hamsters for pets is 30.4%.
Use the image to answer the question.
A bar graph shows pet ownership.
The x-axis shows type of pet and represents dog, cat, golfish, and hamster. The y-axis represents number of students and ranges from 0 to 11 in increments of 1. The data shows 10 dogs; 8 cats; 2 goldfish; and 3 hamsters.
Use the graph to determine the difference in the percentage of students who have dogs for pets and the percentage of students who have hamsters for pets. Round the percentages to the tenths place.
A: The difference in the percentage of students who have dogs for pets and the percentage of students who have hamsters for pets is 30.4%.
B: The difference in the percentage of students who have dogs for pets and the percentage of students who have hamsters for pets is 21.8%.
C: The difference in the percentage of students who have dogs for pets and the percentage of students who have hamsters for pets is 34.8%.
D: The difference in the percentage of students who have dogs for pets and the percentage of students who have hamsters for pets is 31%.
9 answers
Use the image to answer the question.
A pie chart divided into 6 inequal sections is titled Activity Hours per Week. The sections are labeled school, 40, 24 percent; eat, 21, 13 percent; sports or play, 15, 9 percent; social media or TV, 24, 14 percent; sleep, 56; and other 12, 7 percent.
The activity for one week of 168 people was tracked and displayed in a circle graph. What was the percentage of time spent on sleep? Round the percentage to the nearest whole number.
The percentage of time spent on sleep was ___%
A pie chart divided into 6 inequal sections is titled Activity Hours per Week. The sections are labeled school, 40, 24 percent; eat, 21, 13 percent; sports or play, 15, 9 percent; social media or TV, 24, 14 percent; sleep, 56; and other 12, 7 percent.
The activity for one week of 168 people was tracked and displayed in a circle graph. What was the percentage of time spent on sleep? Round the percentage to the nearest whole number.
The percentage of time spent on sleep was ___%
To find the percentage of time spent on sleep, you would divide the number of hours spent on sleep by the total number of hours in a week (168 hours) and then multiply by 100 to get the percentage.
Sleep time: 56 hours
Total time in a week: 168 hours
Percentage of time spent on sleep: (56/168) * 100 = 33.3%
Rounded to the nearest whole number, the percentage of time spent on sleep is 33%.
Sleep time: 56 hours
Total time in a week: 168 hours
Percentage of time spent on sleep: (56/168) * 100 = 33.3%
Rounded to the nearest whole number, the percentage of time spent on sleep is 33%.
Which data set has the highest median?
A: {8, 20, 13, 14, 12, 9}
B: {1, 6, 15, 7, 15, 18, 14}
C: {1, 10, 8, 29, 14, 17, 3}
D: {11, 15, 16, 8, 12, 14}
A: {8, 20, 13, 14, 12, 9}
B: {1, 6, 15, 7, 15, 18, 14}
C: {1, 10, 8, 29, 14, 17, 3}
D: {11, 15, 16, 8, 12, 14}
To determine which data set has the highest median, we need to find the median of each set.
A: {8, 20, 13, 14, 12, 9}
Arranging in ascending order: {8, 9, 12, 13, 14, 20}
Median = (12 + 13) / 2 = 12.5
B: {1, 6, 15, 7, 15, 18, 14}
Arranging in ascending order: {1, 6, 7, 14, 15, 15, 18}
Median = 14
C: {1, 10, 8, 29, 14, 17, 3}
Arranging in ascending order: {1, 3, 8, 10, 14, 17, 29}
Median = 10
D: {11, 15, 16, 8, 12, 14}
Arranging in ascending order: {8, 11, 12, 14, 15, 16}
Median = (12 + 14) / 2 = 13
Among the four data sets, the one with the highest median is set B: {1, 6, 15, 7, 15, 18, 14} as it has a median of 14.
A: {8, 20, 13, 14, 12, 9}
Arranging in ascending order: {8, 9, 12, 13, 14, 20}
Median = (12 + 13) / 2 = 12.5
B: {1, 6, 15, 7, 15, 18, 14}
Arranging in ascending order: {1, 6, 7, 14, 15, 15, 18}
Median = 14
C: {1, 10, 8, 29, 14, 17, 3}
Arranging in ascending order: {1, 3, 8, 10, 14, 17, 29}
Median = 10
D: {11, 15, 16, 8, 12, 14}
Arranging in ascending order: {8, 11, 12, 14, 15, 16}
Median = (12 + 14) / 2 = 13
Among the four data sets, the one with the highest median is set B: {1, 6, 15, 7, 15, 18, 14} as it has a median of 14.
Fifteen students are randomly selected from two different classes. They were asked how many books they read during the summer. Their responses are as follows. Find the median number of books read by each class. Which class has a higher median number of books read?
Class 1: 0, 5, 3, 6, 7, 8, 10, 1, 1, 4, 5, 6, 4, 5, 6
Class 2: 2, 2, 4, 3, 0, 0, 6, 7, 10, 9, 6, 5, 3, 1, 2
The median number of books read during the summer by Class 1 is ___
The median number of books read during the summer by Class 2 is ____
Class ___ has a higher median number of books read during the summer.
Class 1: 0, 5, 3, 6, 7, 8, 10, 1, 1, 4, 5, 6, 4, 5, 6
Class 2: 2, 2, 4, 3, 0, 0, 6, 7, 10, 9, 6, 5, 3, 1, 2
The median number of books read during the summer by Class 1 is ___
The median number of books read during the summer by Class 2 is ____
Class ___ has a higher median number of books read during the summer.
To find the median number of books read for each class, we must first order the data.
For Class 1:
0, 1, 1, 3, 4, 4, 5, 5, 5, 6, 6, 6, 7, 8, 10
There are 15 students, so the median would be the average of the 8th and 9th values.
Median for Class 1: (5 + 5) / 2 = 5
For Class 2:
0, 0, 1, 2, 2, 2, 3, 3, 4, 5, 6, 6, 7, 9, 10
There are 15 students, so the median would be the 8th value.
Median for Class 2: 3
Therefore, the median number of books read during the summer by:
Class 1 is 5
Class 2 is 3
Hence, Class 1 has a higher median number of books read during the summer.
For Class 1:
0, 1, 1, 3, 4, 4, 5, 5, 5, 6, 6, 6, 7, 8, 10
There are 15 students, so the median would be the average of the 8th and 9th values.
Median for Class 1: (5 + 5) / 2 = 5
For Class 2:
0, 0, 1, 2, 2, 2, 3, 3, 4, 5, 6, 6, 7, 9, 10
There are 15 students, so the median would be the 8th value.
Median for Class 2: 3
Therefore, the median number of books read during the summer by:
Class 1 is 5
Class 2 is 3
Hence, Class 1 has a higher median number of books read during the summer.
Use the image to answer the question.
Two number lines extend from 41 to 50 in increments of 1 and are labeled as Dataset A and Dataset B. The number lines show an abacus-like representation with columns of open circles over the numbers. Above the number line labeled Dataset A, there are four circles over 41, five circles over 42, seven circles over 43, four circles over 44, two circles over 45, one circle over 46, one circle over 47, three circles over 48, two circles over 49, and one circle over 50. Above the number line labeled Dataset B, there is one circle over 41, three circles over 42, three circles over 43, five circles over 44, four circles over 45, six circles over 46, seven circles over 47, four circles over 48, two circles over 49, and one circle over 50.
Two datasets of numbers from 41 to 50 are displayed in two dot plots. Compare the shapes and spreads of the dot plots. What conclusions can you draw about the shapes and the spreads?
A: Dataset A and Dataset B have equal spreads. Dataset A is skewed right, and Dataset B is symmetrical. Dataset A has a peak at 43. Dataset B has a peak at 47.
B: Dataset A and Dataset B have equal spreads. Dataset A is skewed left, and Dataset B is symmetrical. Dataset A has a peak at 43. Dataset B has a peak at 47.
C: Dataset A and Dataset B have equal spreads. Dataset A is skewed right, and Dataset B is symmetrical. Dataset A has a peak at 42. Dataset B has a peak at 46.
D: Dataset A has a greater spread than Dataset B. Dataset A is skewed right, and Dataset B is symmetrical. Dataset A has a peak at 43. Dataset B has a peak at 47.
Two number lines extend from 41 to 50 in increments of 1 and are labeled as Dataset A and Dataset B. The number lines show an abacus-like representation with columns of open circles over the numbers. Above the number line labeled Dataset A, there are four circles over 41, five circles over 42, seven circles over 43, four circles over 44, two circles over 45, one circle over 46, one circle over 47, three circles over 48, two circles over 49, and one circle over 50. Above the number line labeled Dataset B, there is one circle over 41, three circles over 42, three circles over 43, five circles over 44, four circles over 45, six circles over 46, seven circles over 47, four circles over 48, two circles over 49, and one circle over 50.
Two datasets of numbers from 41 to 50 are displayed in two dot plots. Compare the shapes and spreads of the dot plots. What conclusions can you draw about the shapes and the spreads?
A: Dataset A and Dataset B have equal spreads. Dataset A is skewed right, and Dataset B is symmetrical. Dataset A has a peak at 43. Dataset B has a peak at 47.
B: Dataset A and Dataset B have equal spreads. Dataset A is skewed left, and Dataset B is symmetrical. Dataset A has a peak at 43. Dataset B has a peak at 47.
C: Dataset A and Dataset B have equal spreads. Dataset A is skewed right, and Dataset B is symmetrical. Dataset A has a peak at 42. Dataset B has a peak at 46.
D: Dataset A has a greater spread than Dataset B. Dataset A is skewed right, and Dataset B is symmetrical. Dataset A has a peak at 43. Dataset B has a peak at 47.
Analyzing the data in the dot plots for Dataset A and Dataset B:
- Dataset A has values that go up to 7, while Dataset B has values that go up to 7 as well.
- The distribution of values for Dataset A seems to have a peak around 43, with the number of circles decreasing as you move away from it. This indicates a skewed right shape.
- The distribution of values for Dataset B appears to be more consistent, with no pronounced peak. This suggests a symmetrical shape.
Therefore, based on the descriptions of the shapes and spreads of the dot plots, the correct conclusion is:
C: Dataset A and Dataset B have equal spreads. Dataset A is skewed right, and Dataset B is symmetrical. Dataset A has a peak at 42. Dataset B has a peak at 46.
- Dataset A has values that go up to 7, while Dataset B has values that go up to 7 as well.
- The distribution of values for Dataset A seems to have a peak around 43, with the number of circles decreasing as you move away from it. This indicates a skewed right shape.
- The distribution of values for Dataset B appears to be more consistent, with no pronounced peak. This suggests a symmetrical shape.
Therefore, based on the descriptions of the shapes and spreads of the dot plots, the correct conclusion is:
C: Dataset A and Dataset B have equal spreads. Dataset A is skewed right, and Dataset B is symmetrical. Dataset A has a peak at 42. Dataset B has a peak at 46.
1 answer