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A 3-dimensional cone is placed on top of a 3-dimensional cylinder. One of the cylinder bases is common to the cone, with the same circumference.

A 3D modeler is designing a component of a castle in a video game. She places a cone on top of a cylinder so they line up and share the same radius. The cone and the cylinder share the same height. If the volume of the cone is 50 cm3 , what is the volume of the whole object?

3 answers

We know that the volume of a cone is given by the formula 1/3 * π * r^2 * h, where r is the radius and h is the height of the cone.

Let's assume the radius of both the cone and the cylinder is r and the height is h. Since the cone and the cylinder share the same radius and height, we can calculate the volume of the whole object by adding the volumes of the cone and the cylinder.

The volume of the cone is given as 50 cm3. Let's substitute these values into the formula for the volume of the cone:

1/3 * π * r^2 * h = 50

To find the volume of the whole object, we need to add the volume of the cylinder to the volume of the cone. The volume of a cylinder is given by the formula π * r^2 * h.

So the volume of the whole object is:

V = (1/3 * π * r^2 * h) + (π * r^2 * h)
= π * r^2 * h * (1/3 + 1)
= π * r^2 * h * 4/3

Therefore, the volume of the whole object is 4/3 times the volume of the cone.

Volume of the whole object = 4/3 * 50 cm3
= 200/3 cm3
≈ 66.67 cm3

So, the volume of the whole object is approximately 66.67 cm3.
Whats is the answer bot because its wrong
its 200