Question

Use the image to answer the question. 1 ft. 8 ft. 4 ft. 4 ft. 2 ft. 5 ft. 2 ft. Jenny is painting her little brother's wall with a rocket ship design. How much area does the rocket ship design take? (4 points)

Answer 1

To calculate the area of the rocket ship design you would typically break it down into simpler shapes like rectangles and triangles, based on the dimensions provided:

1. The rocket ship seems to be composed of multiple sections. Each section's area can be computed using its respective dimensions.
2. You have given dimensions including 1 ft, 8 ft, 4 ft, 4 ft, 2 ft, 5 ft, and 2 ft, which correspond to different sections of the rocket ship.

Let’s assume the design consists of:
- A rectangle at the bottom (width: 4 ft, height: 8 ft)
- A triangle on top for the tip of the rocket (base width: 4 ft, height: 5 ft)
- Two small rectangular fins at the sides (each 2 ft wide and 4 ft high)

### Calculations:
1. **Area of the Rectangular Body**:
\[
\text{Area} = \text{width} \times \text{height} = 4 \, \text{ft} \times 8 \, \text{ft} = 32 \, \text{sq ft}
\]

2. **Area of the Triangular Tip** (\( \text{Area} = \frac{1}{2} \times \text{base} \times \text{height} \)):
\[
\text{Area} = \frac{1}{2} \times 4 \, \text{ft} \times 5 \, \text{ft} = \frac{20}{2} = 10 \, \text{sq ft}
\]

3. **Area of the Fins** (Assuming 2 fins each with area):
\[
\text{Area of one fin} = \text{width} \times \text{height} = 2 \, \text{ft} \times 4 \, \text{ft} = 8 \, \text{sq ft}
\]
\[
\text{Total Area of Fins} = 2 \times 8 \, \text{sq ft} = 16 \, \text{sq ft}
\]

### Total Area:
\[
\text{Total Area} = \text{Area of Rectangle} + \text{Area of Triangle} + \text{Area of Fins}
\]
\[
= 32 \, \text{sq ft} + 10 \, \text{sq ft} + 16 \, \text{sq ft} = 58 \, \text{sq ft}
\]

Thus, the total area that the rocket ship design takes is **58 square feet**.