To calculate the area of the rocket ship design you would typically break it down into simpler shapes like rectangles and triangles, based on the dimensions provided:
- The rocket ship seems to be composed of multiple sections. Each section's area can be computed using its respective dimensions.
- You have given dimensions including 1 ft, 8 ft, 4 ft, 4 ft, 2 ft, 5 ft, and 2 ft, which correspond to different sections of the rocket ship.
Let’s assume the design consists of:
- A rectangle at the bottom (width: 4 ft, height: 8 ft)
- A triangle on top for the tip of the rocket (base width: 4 ft, height: 5 ft)
- Two small rectangular fins at the sides (each 2 ft wide and 4 ft high)
Calculations:
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Area of the Rectangular Body: \[ \text{Area} = \text{width} \times \text{height} = 4 , \text{ft} \times 8 , \text{ft} = 32 , \text{sq ft} \]
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Area of the Triangular Tip (\( \text{Area} = \frac{1}{2} \times \text{base} \times \text{height} \)): \[ \text{Area} = \frac{1}{2} \times 4 , \text{ft} \times 5 , \text{ft} = \frac{20}{2} = 10 , \text{sq ft} \]
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Area of the Fins (Assuming 2 fins each with area): \[ \text{Area of one fin} = \text{width} \times \text{height} = 2 , \text{ft} \times 4 , \text{ft} = 8 , \text{sq ft} \] \[ \text{Total Area of Fins} = 2 \times 8 , \text{sq ft} = 16 , \text{sq ft} \]
Total Area:
\[ \text{Total Area} = \text{Area of Rectangle} + \text{Area of Triangle} + \text{Area of Fins} \] \[ = 32 , \text{sq ft} + 10 , \text{sq ft} + 16 , \text{sq ft} = 58 , \text{sq ft} \]
Thus, the total area that the rocket ship design takes is 58 square feet.
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