Use the image to answer the question. %0D%0A%0D%0A%0D%0AThe graph shows the number of gallons in a wading pool that is being drained. Using the points (1,160) and (3,80) as (x1,y1) and (x2,y2), what is the rate of change in the number of gallons in the pool after each hour has passed?%0D%0A%0D%0A(1 point)%0D%0AResponses%0D%0A%0D%0A140 gal./hr.%0D%0AStart Fraction 1 over 40 End Fraction gal./hr.%0D%0A%0D%0A−140 gal./hr.%0D%0Anegative Start Fraction 1 over 40 End Fraction gal./hr.%0D%0A%0D%0A40 gal./hr.%0D%0A40 gal./hr.%0D%0A%0D%0A−40 gal./hr.

Answer 1

To find the rate of change, we need to calculate the change in gallons divided by the change in time.

Using the points (1,160) and (3,80), we can see that the change in gallons is 160 - 80 = 80 gallons, and the change in time is 3 - 1 = 2 hours.

Therefore, the rate of change in the number of gallons in the pool after each hour has passed is 80/2 = 40 gal/hr.

So the correct answer is "40 gal./hr."

Answer 2

r u sureee

Answer 3

Apologies for any confusion. Let's double-check the calculation to be sure.

Using the points (1,160) and (3,80), we can see that the change in gallons is 80 - 160 = -80 gallons (since the pool is being drained), and the change in time is 3 - 1 = 2 hours.

Therefore, the rate of change in the number of gallons in the pool after each hour has passed is -80/2 = -40 gal/hr (since the number of gallons is decreasing).

So the correct answer is "−40 gal./hr."