balance the reaction equation:
2C6H10+17O2>>12CO2 + 10H20 check that.
so you get 12 moles CO2 for each 2 mole of C6H10
molesCO2=12/2 * moles C6H10=6*35/molmassC6H10
figure that out. Then,
PV=nRT
V=nRT/P where n is moles CO2, you are given T (change it to K). Watch units of R, you are in kelvins, atm
Use the Ideal Gas Law to determine the volume of CO2 produced at 25oC 1.5 atm of pressure from the combustion of 35 grams of C6H10.
1 answer