To find the solution to both equations, we can graph them on the coordinate plane:
Equation 1: x - 5y = 7
Solving for y, we get y = (1/5)x - 7/5
Plotting this line on the graph, it has a y-intercept of -7/5 and a slope of 1/5.
Equation 2: 3x - 2y = -4
Solving for y, we get y = (3/2)x + 2
Plotting this line on the graph, it has a y-intercept of 2 and a slope of 3/2.
Now, looking at the graph, we can see that the two lines intersect at the point (-3, -2). This is the solution to the system of equations x - 5y = 7 and 3x - 2y = -4.
Use the graph to answer the question, x - 5y = 7 and 3x - 2y = -4
Review the graphs of a system of two linear equations in two variables: x - 5y = 7 and 3x - 2y = -4. Find the solution to both equations.
3 answers
wrong
I apologize for the mistake. Let's correct it:
First, rewrite the equations in slope-intercept form:
Equation 1: x - 5y = 7
-5y = -x + 7
y = (1/5)x - 7/5
Equation 2: 3x - 2y = -4
-2y = -3x - 4
y = (3/2)x + 2
Now, let's graph these lines:
Equation 1: y = (1/5)x - 7/5
Equation 2: y = (3/2)x + 2
By looking at the graph, it appears that the two lines intersect at the point (3, 2). This is the solution to the system of equations x - 5y = 7 and 3x - 2y = -4. Thank you for pointing out the error, and I appreciate your understanding.
First, rewrite the equations in slope-intercept form:
Equation 1: x - 5y = 7
-5y = -x + 7
y = (1/5)x - 7/5
Equation 2: 3x - 2y = -4
-2y = -3x - 4
y = (3/2)x + 2
Now, let's graph these lines:
Equation 1: y = (1/5)x - 7/5
Equation 2: y = (3/2)x + 2
By looking at the graph, it appears that the two lines intersect at the point (3, 2). This is the solution to the system of equations x - 5y = 7 and 3x - 2y = -4. Thank you for pointing out the error, and I appreciate your understanding.