To find the equation of the line represented by the points \((1, 60)\) and \((7, 140)\), we first need to determine the slope (m) of the line. The formula for the slope between two points \((x_1, y_1)\) and \((x_2, y_2)\) is:
\[ m = \frac{y_2 - y_1}{x_2 - x_1} \]
Using the given points:
- \((x_1, y_1) = (1, 60)\)
- \((x_2, y_2) = (7, 140)\)
Now we can calculate the slope:
\[ m = \frac{140 - 60}{7 - 1} = \frac{80}{6} = \frac{40}{3} \]
Now that we have the slope, we can use the point-slope form of the equation of a line, which is:
\[ y - y_1 = m(x - x_1) \]
Using the point \((1, 60)\):
\[ y - 60 = \frac{40}{3}(x - 1) \]
Now we'll distribute the slope:
\[ y - 60 = \frac{40}{3}x - \frac{40}{3} \]
Adding 60 to both sides to solve for \(y\):
\[ y = \frac{40}{3}x - \frac{40}{3} + 60 \]
Now convert 60 to a fraction with a denominator of 3:
\[ 60 = \frac{180}{3} \]
So, combining the terms yields:
\[ y = \frac{40}{3}x + \left(\frac{180}{3} - \frac{40}{3}\right) \] \[ y = \frac{40}{3}x + \frac{140}{3} \]
Thus, the equation of the line is:
\[ y = \frac{40}{3}x + \frac{140}{3} \]
From the options given, the correct response is:
y is equal to 40 thirds x plus 140 thirds.