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Use the graph to answer the question. The graph shows an exponentially decreasing line passing through (0, 8) and (1, 6) Write...Question
Use the graph to answer the question.
The graph shows an exponentially decreasing line passing through (-1, 10) and (1, 3.6)
Write the exponential equation shown in the graph.
The graph shows an exponentially decreasing line passing through (-1, 10) and (1, 3.6)
Write the exponential equation shown in the graph.
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Answered by
GPT-4o mini
To find the exponential equation that fits the points given in the problem, we can use the general form of an exponential function:
\[
y = ab^x
\]
where \( a \) is the initial value (when \( x = 0 \)) and \( b \) is the base that determines the rate of decay.
Given the points (-1, 10) and (1, 3.6), we can set up a system of equations to find \( a \) and \( b \).
1. For the point (-1, 10):
\[
10 = ab^{-1} \quad \text{(Equation 1)}
\]
This simplifies to:
\[
10 = \frac{a}{b} \quad \Rightarrow \quad a = 10b \quad \text{(Equation 1.1)}
\]
2. For the point (1, 3.6):
\[
3.6 = ab^{1} \quad \text{(Equation 2)}
\]
This can be written as:
\[
3.6 = ab \quad \text{(Equation 2.1)}
\]
Now, we can substitute Equation 1.1 into Equation 2.1:
\[
3.6 = (10b)b
\]
\[
3.6 = 10b^2
\]
Now, solve for \( b^2 \):
\[
b^2 = \frac{3.6}{10} = 0.36
\]
\[
b = \sqrt{0.36} = 0.6
\]
Now that we have found \( b \), we can use Equation 1.1 to find \( a \):
\[
a = 10b = 10 \times 0.6 = 6
\]
So, the exponential equation is:
\[
y = 6(0.6)^x
\]
Thus, the exponential equation shown in the graph is:
\[
y = 6(0.6)^x
\]
\[
y = ab^x
\]
where \( a \) is the initial value (when \( x = 0 \)) and \( b \) is the base that determines the rate of decay.
Given the points (-1, 10) and (1, 3.6), we can set up a system of equations to find \( a \) and \( b \).
1. For the point (-1, 10):
\[
10 = ab^{-1} \quad \text{(Equation 1)}
\]
This simplifies to:
\[
10 = \frac{a}{b} \quad \Rightarrow \quad a = 10b \quad \text{(Equation 1.1)}
\]
2. For the point (1, 3.6):
\[
3.6 = ab^{1} \quad \text{(Equation 2)}
\]
This can be written as:
\[
3.6 = ab \quad \text{(Equation 2.1)}
\]
Now, we can substitute Equation 1.1 into Equation 2.1:
\[
3.6 = (10b)b
\]
\[
3.6 = 10b^2
\]
Now, solve for \( b^2 \):
\[
b^2 = \frac{3.6}{10} = 0.36
\]
\[
b = \sqrt{0.36} = 0.6
\]
Now that we have found \( b \), we can use Equation 1.1 to find \( a \):
\[
a = 10b = 10 \times 0.6 = 6
\]
So, the exponential equation is:
\[
y = 6(0.6)^x
\]
Thus, the exponential equation shown in the graph is:
\[
y = 6(0.6)^x
\]
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