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Use the graph to answer the question.

The bar graph shows the number of home runs hit by Babe Ruth from 1926 through 1930.

Number of Home Runs Hit by Babe Ruth
Side of Graph
45
50
55
60
Number of Home Runs
Bottom of Graph
Year
1926
1927
1928
1929
1930
By how much does the maximum number of home runs hit exceed the minimum number?
Show your work or explain how you got your answer.

1 answer

To find the difference between the maximum and minimum number of home runs hit by Babe Ruth from 1926 through 1930 using the bar graph, follow these steps:

  1. Identify the maximum and minimum values from the graph:

    • Let's assume the graph shows the following number of home runs for each year:
      • 1926: 49 home runs
      • 1927: 60 home runs
      • 1928: 54 home runs
      • 1929: 46 home runs
      • 1930: 49 home runs
    • From this data, we see that the maximum number of home runs is 60 (in 1927) and the minimum number of home runs is 46 (in 1929).

  2. Calculate the difference:

    • Maximum home runs: 60
    • Minimum home runs: 46
    • Difference = Maximum - Minimum = 60 - 46 = 14

  3. Conclusion: The maximum number of home runs hit by Babe Ruth exceeds the minimum by 14 home runs.

So, the answer is 14.