Use the graph to answer the question. The bar graph shows the number of home runs hit by Babe Ruth from 1926 through 1930. By how much does the maximum number of home runs hit exceed the minimum number?

Question

graph says in 1926 he hit about 47 home runs in 1927 he hit 60 in 1928 he hit 54 in 1929 he hit 46 in 1930 he hit 48

Answer 1

To find the difference between the maximum and minimum number of home runs hit by Babe Ruth from 1926 to 1930, we first identify the maximum and minimum values from the data provided:

• 1926: 47 home runs
• 1927: 60 home runs (maximum)
• 1928: 54 home runs
• 1929: 46 home runs (minimum)
• 1930: 48 home runs

The maximum number of home runs is 60 (from 1927) and the minimum is 46 (from 1929).

Now, we calculate the difference:

Maximum - Minimum = 60 - 46 = 14

Therefore, the maximum number of home runs hit exceeds the minimum number by 14.