To find the intersection points of the system of equations, we first need to graph the equations on the same coordinate plane.
For the first equation 3x-2y=-4, we can rewrite it in slope-intercept form as y = (3/2)x + 2. This equation has a y-intercept of 2 and a slope of 3/2.
For the second equation x-5y=3, we can rewrite it in slope-intercept form as y = (1/5)x - 3/5. This equation has a y-intercept of -3/5 and a slope of 1/5.
When we graph both equations on the same coordinate plane, we will see that they intersect at the point (1, -1).
Therefore, the solution to both equations is x = 1 and y = -1.
Use the graph to answer the question 3x-2y=-4
X-5y=3
Review the graph of a system of two linear equations in two variables x-5y=7 and 3x-2y=-4 find the solution of both equations
What's the intersection points?
3 answers
1 or -1 isn't the intersection, do it again
I apologize for the mistake. Let's find the correct intersection point.
We have the system of equations:
1) x - 5y = 7
2) 3x - 2y = -4
To find the intersection point, we can solve this system of equations simultaneously.
We can rewrite equation 1 in terms of x:
x = 7 + 5y
Now substitute this expression for x into equation 2:
3(7 + 5y) - 2y = -4
21 + 15y - 2y = -4
13y = -25
y = -25/13
Now substitute y back into x = 7 + 5y:
x = 7 + 5(-25/13)
x = 7 - 125/13
x = 66/13 - 125/13
x = -59/13
Therefore, the intersection point of the two equations is (-59/13, -25/13).
We have the system of equations:
1) x - 5y = 7
2) 3x - 2y = -4
To find the intersection point, we can solve this system of equations simultaneously.
We can rewrite equation 1 in terms of x:
x = 7 + 5y
Now substitute this expression for x into equation 2:
3(7 + 5y) - 2y = -4
21 + 15y - 2y = -4
13y = -25
y = -25/13
Now substitute y back into x = 7 + 5y:
x = 7 + 5(-25/13)
x = 7 - 125/13
x = 66/13 - 125/13
x = -59/13
Therefore, the intersection point of the two equations is (-59/13, -25/13).