Use the graph of f(t) = 2t + 4 on the interval [−4, 6] to write the function F(x), where f of x equals the integral from 2 to x of f of t dt.

Answer 1

F(x) = ∫(2t + 4) dt from 2 to x
= t^2 + t | from 2 to x
= x^2 + x - (4 + 2)
= x^2 + x - 6

Answer 2

F(x) = ∫(2t + 4) dt from 2 to x
= t^2 + 4t | from 2 to x
= x^2 + 4x - (4 + 2*4)
= x^2 + 4x - (4 + 8)

=> x^2 + x - 12

Answer 3

Yes the answer is x^2 + x - 12
I confirmed it!