(3 - 5i) and (3+5i)
therefore divide by product(x-3+5i) and (x-3-5i)
or
(x^2 - 6 x + 34)
so do long division
x^4-9x^3+12x^2+138x-1360
-------------------------
x^2 - 6 x + 34
which is (x^2-3x-40) whew, no remainder
find the two zeros of that
x = [ 3 +/- sqrt (9+160)]/2
= [3+/-13]/2
= -5 and 8
so in the end
-5
+8
-3-5i
-3+5i
use the given zeros to find the remaining zeros of the function
h(x)=x^4-9x^3+12x^2+138x-1360
zero:3-5i
enter the remaining zeros of f
please show work
3 answers
That was fun :)
-5
+8
3-5i
3+5i
+8
3-5i
3+5i