we can find B using the sine law
sinB/100 = sin110/125
sinB = .75175
B = 48.74
then C = 21.26
Now Area = (1/2)(100)(125)sin 21.26 = 2265.99
Use the given information to solve the triangle. If two solutions exists, find both.
A=110 degrees
a=125
b=100
a is greater than b so I think that there is only one triangle. I am not sure where to go from here.
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Thank You!!
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