Use the given information to find the p-value: the test statistic is a left-tailed test and z=-1.25 (normal distribution).

Round your answer to nearest thousandths.

1 answer

To find the p-value for a left-tailed test with a test statistic of \( z = -1.25 \), you can use the standard normal distribution (Z-distribution).

  1. You can look up the value of \( z = -1.25 \) in a standard normal distribution table, or you can use a calculator or statistical software that provides cumulative probabilities for the standard normal distribution.

Using a standard normal distribution table or calculator:

  • The cumulative probability (p-value) associated with \( z = -1.25 \) is approximately \( 0.1056 \).

Therefore, rounding to the nearest thousandths, the p-value is:

\[ \text{p-value} \approx 0.106 \]

So, the final answer is \( \mathbf{0.106} \).