Use the given data at 298 K to calculate ¦¤G¡ã for the reaction
2NO(g) + 2H2(g) ¡ú N2(g) + 2H2O(g)
Substance NO(g) H2(g) N2(g) H2O(g)
¦¤H¡ãf (kJ/mol) 90 0 0 -242
S¡ã(J/K¡¤mol) 211 131 192 189
a. -270 kJ
b. -630 kJ
c. -3.46 x 104 kJ
d. -667 kJ
6 answers
B. -630 kJ
WELL YOURE WELCOME !!!!!!!!!!!!!!!!GEEZ!
gaby can you show me how you did this? i kept getting 333
well what do you think youre doing wrong?
BTW would you mind helping me with my algebra 1 question cuz i really don't get it?!?!?!?!
i figured dH to = -664, the dS = -114.
then i use equation>
dG = dH -TdSand i got 333.08 kJ
then i use equation>
dG = dH -TdSand i got 333.08 kJ
1 answer