To compute the perimeter of the triangle with the given vertices at coordinates (1,6), (1,2), and (-4,2), we first need to find the lengths of each side using the distance formula. The distance \(d\) between two points \((x_1, y_1)\) and \((x_2, y_2)\) is given by:
\[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \]
Step 1: Calculate the lengths of each side
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Length of side between (1,6) and (1,2): \[ d_1 = \sqrt{(1 - 1)^2 + (2 - 6)^2} = \sqrt{0 + (-4)^2} = \sqrt{16} = 4 \]
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Length of side between (1,2) and (-4,2): \[ d_2 = \sqrt{(-4 - 1)^2 + (2 - 2)^2} = \sqrt{(-5)^2 + 0} = \sqrt{25} = 5 \]
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Length of side between (-4,2) and (1,6): \[ d_3 = \sqrt{(1 - (-4))^2 + (6 - 2)^2} = \sqrt{(1 + 4)^2 + (4)^2} = \sqrt{5^2 + 4^2} = \sqrt{25 + 16} = \sqrt{41} \]
Step 2: Calculate the perimeter
Now we sum the lengths of the sides to find the perimeter \(P\):
\[ P = d_1 + d_2 + d_3 = 4 + 5 + \sqrt{41} \]
Calculating \(\sqrt{41}\): \[ \sqrt{41} \approx 6.4 \]
Thus, the perimeter becomes: \[ P \approx 4 + 5 + 6.4 = 15.4 \]
Step 3: Round to the nearest tenth
The perimeter of the triangle, rounded to the nearest tenth, is: \[ \boxed{15.4} \]