Use the Fundamental Theorem of Algebra to determine which of the following equations have two solutions. Explain your reasoning in 3–5 sentences.%0D%0A%0D%0Aa. −9x+4x2+3=0%0D%0A%0D%0Ab. −2x2−5=0%0D%0A%0D%0Ac. 57x2=0%0D%0A%0D%0Ad. 0x2+7x−2=0%0D%0A%0D%0Ae. 0x3−x2+2x+4=0

1 answer

The Fundamental Theorem of Algebra states that a polynomial of degree \( n \) will have exactly \( n \) roots, counted with multiplicity. To determine which equations have two solutions, we need to assess the degree of each polynomial:

a. The equation \(-9x + 4x^2 + 3 = 0\) is a quadratic equation (degree 2) and has two solutions.

b. The equation \(-2x^2 - 5 = 0\) is also a quadratic (degree 2) and will have two solutions.

c. The equation \(57x^2 = 0\) is again quadratic, but it gives a double root at \(x = 0\), counting as one unique solution.

d. The equation \(0x^2 + 7x - 2 = 0\) simplifies to \(7x - 2 = 0\), which is linear (degree 1) and has one solution.

e. The equation \(0x^3 - x^2 + 2x + 4 = 0\) simplifies to \(-x^2 + 2x + 4 = 0\), which is also quadratic (degree 2) and will have two solutions.

Thus, the equations with two solutions are (a), (b), and (e).