Use the functions below.

Question

f(x)=x−2
g(x)=2x
h(x)=x+7−−−−√
What is (f⋅g⋅h)(x)
? What is the domain of (f⋅g⋅h)(x)
?

(1 point)
Responses

(f⋅g⋅h)(x)=2xxx+7−−−−−√−2x+1x+7−−−−−√
and the domain of (f⋅g⋅h)(x)
is (−∞,∞)
.
open paren f times g times h close paren times x is equal to 2 to the x th power x square root of x plus 7 end root minus 2 raised to the x plus 1 power square root of x plus 7 end root and the domain of open paren f times g times h close paren times x is open paren negative infinity comma infinity close paren .

(f⋅g⋅h)(x)=2xxx+7−−−−−√−2x+1x+7−−−−−√
and the domain of (f⋅g⋅h)(x)
is x≥−7
.
open paren f times g times h close paren times x is equal to 2 to the x th power x square root of x plus 7 end root minus 2 raised to the x plus 1 power square root of x plus 7 end root and the domain of open paren f times g times h close paren times x is x is greater than or equal to negative 7 .

(f⋅g⋅h)(x)=x−2+2x+x+7−−−−−√
and the domain of (f⋅g⋅h)(x)
is x≥−7
.
open paren f times g times h close paren times x is equal to x minus 2 plus 2 to the x th power plus square root of x plus 7 end root and the domain of open paren f times g times h close paren times x is x is greater than or equal to negative 7 .

(f⋅g⋅h)(x)=x−2+2x+x+7−−−−−√
and the domain of (f⋅g⋅h)(x)
is (−∞,∞)
.

Answer 1

To find \((f \cdot g \cdot h)(x)\), we will first express it in terms of the given functions and then determine the domain.

Given Functions:

• \( f(x) = x - 2 \)
• \( g(x) = 2x \)
• \( h(x) = \sqrt{x + 7} \)

Calculating \((f \cdot g \cdot h)(x)\): \[ (f \cdot g \cdot h)(x) = f(x) \cdot g(x) \cdot h(x) \]

Substituting the functions: \[ = (x - 2) \cdot (2x) \cdot \sqrt{x + 7} \]

Now, we simplify it:

1. First, calculate \(f(x) \cdot g(x)\): \[ f(x) \cdot g(x) = (x - 2)(2x) = 2x^2 - 4x \]

2. Now multiply by \(h(x)\): \[ (2x^2 - 4x) \cdot \sqrt{x + 7} = (2x^2 - 4x) \sqrt{x + 7} \]

Thus, we have: \[ (f \cdot g \cdot h)(x) = (2x^2 - 4x) \sqrt{x + 7} \]

Finding the Domain: The domain of \((f \cdot g \cdot h)(x)\) is determined by the domain restrictions of the functions involved:

• For \(f(x) = x - 2\), there are no restrictions: it is defined for all \(x \in (-\infty, \infty)\).
• For \(g(x) = 2x\), there are also no restrictions: it is defined for all \(x \in (-\infty, \infty)\).
• For \(h(x) = \sqrt{x + 7}\), we require: \[ x + 7 \geq 0 \implies x \geq -7 \]

Therefore, the domain of \((f \cdot g \cdot h)(x)\) is: \[ x \geq -7 \text{ or } [-7, \infty) \]

Final Answer: \((f \cdot g \cdot h)(x) = (2x^2 - 4x) \sqrt{x + 7}\)

And the domain of \((f \cdot g \cdot h)(x)\) is \(x \geq -7\) or \( [-7, \infty) \).