To find \((f - g - h)(x)\), we first need to consider each function:
- \(f(x) = 5x^2 + 3x - 6\)
- \(g(x) = |x + 1| - 7\)
- \(h(x) = -x^4 + 2x^2 + 3\)
Now let's compute \((f - g - h)(x)\):
\[ (f - g - h)(x) = f(x) - g(x) - h(x) \]
Substituting the expressions for \(f(x)\), \(g(x)\), and \(h(x)\):
\[ = (5x^2 + 3x - 6) - (|x + 1| - 7) - (-x^4 + 2x^2 + 3) \]
Now let's simplify this step by step:
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Rewrite \(g(x)\) as \(-|x + 1| + 7\): \[ -g(x) = -|x + 1| + 7 \]
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Substitute \(h(x)\) as \(+x^4 - 2x^2 - 3\): \[ -h(x) = x^4 - 2x^2 - 3 \]
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Combining everything: \[ (f - g - h)(x) = (5x^2 + 3x - 6) + (-|x + 1| + 7) + (x^4 - 2x^2 - 3) \]
Now collect the like terms:
- The \(x^4\) term: \(x^4\)
- The \(x^2\) terms: \(5x^2 - 2x^2 = 3x^2\)
- The \(x\) terms: \(3x\)
- The constant terms: \(-6 + 7 - 3 = -2\)
Thus, we have: \[ (f - g - h)(x) = x^4 + 3x^2 + 3x - |x + 1| - 2 \]
Therefore, the final expression for \( (f−g−h)(x) \) is: \[ (f - g - h)(x) = x^4 + 3x^2 + 3x - |x + 1| - 2 \]
Next, we determine the domain of \((f - g - h)(x)\). Since \(f(x)\), \(g(x)\), and \(h(x)\) are all polynomials and the absolute value function, they are defined for all real numbers. Thus:
The domain of \((f - g - h)(x)\) is: \[ (-\infty, \infty) \]
In summary: \[ (f - g - h)(x) = x^4 + 3x^2 + 3x - |x + 1| - 2 \quad \text{and the domain is} \quad (-\infty, \infty). \]