To find \((f \cdot g)(x)\), we first need to multiply the two functions \(f(x)\) and \(g(x)\).
Given:
- \(f(x) = 2x - 5\)
- \(g(x) = \sqrt{x + 2}\)
The product of the two functions is: \[ (f \cdot g)(x) = f(x) \cdot g(x) = (2x - 5) \cdot \sqrt{x + 2} \]
Thus, we have: \[ (f \cdot g)(x) = (2x - 5) \sqrt{x + 2} \]
Next, we need to determine the domain of \((f \cdot g)(x)\). The domain of a product function is restricted by the domains of both individual functions.
-
Domain of \(f(x) = 2x - 5\):
- The function \(f(x)\) is a linear function, and it is defined for all real numbers, so its domain is \((-\infty, \infty)\).
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Domain of \(g(x) = \sqrt{x + 2}\):
- The square root function is defined only for non-negative numbers, so we need \(x + 2 \geq 0\).
- This simplifies to \(x \geq -2\).
Because the domain of \((f \cdot g)(x)\) must satisfy both conditions:
- From \(f(x)\): all real numbers
- From \(g(x)\): \(x \geq -2\)
Thus, the overall domain of \((f \cdot g)(x)\) is \(x \geq -2\), or in interval notation, \([-2, \infty)\).
In summary: \[ (f \cdot g)(x) = (2x - 5) \sqrt{x + 2} \] and the domain of \((f \cdot g)(x)\) is \(x \geq -2\).