Use the function f(x) = 3 – x 2 to find

Question

a. f(-2) b. f( 2/3 ) c. f(a + 2)

Answer 1

x is just a place holder. Replace it with whatever you want.
f(x) = 3-x^2
f(0) = 3-0^2 = 3
f(-2) = 3-(-2)^2 = 3-4 = -1
f(a+2) = 3-(a+2)^2 = -a^2-4a-1
f(√3) = 3-(√3)^2 = 3-3 = 0