∫[0,8] 8x-x^2 dx
= 4x^2 - 1/3 x^3 [0,8]
= 4*8^2 - 1/3 * 8^3
= 256 - 512/3
= (768-512)/3
= 256/3
Maybe you should have shown your work.
Use the FTC 1 to find the area of the region under the graph of the function
f(x)= 8x-x^2 on [0,8].
I got 244/3 but the answer key says 256/3.
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