The formula to find the surface area of a right rectangular prism is SA = 2lw + 2lh + 2wh, where l is the length, w is the width, and h is the height.
In this case, all edge lengths measure 12.75, so we can plug this value into the formula:
SA = 2(12.75)(12.75) + 2(12.75)(12.75) + 2(12.75)(12.75) = 2(162.5625) + 2(162.5625) + 2(162.5625) = 325.125 + 325.125 + 325.125 = 975.375 cm^2
Therefore, the correct answer is (1) 975.38 cm^2.
Use the formula to determine the surface area of a right rectangular prism where each edge length measures 12.75 (1 point)
(1) 975.38 cm^2
(2) 5,852.25 cm^2
(3) 76.5 cm^2
(4) 459 cm^2
5 answers
Find the surface area of a textbook that is 2 in. x 14 in. x 9 in. (1 point)
(1) 172 in.^2
(2) 252 in.^2
(3) 50 in.^2
(4) 344 in.^2
(1) 172 in.^2
(2) 252 in.^2
(3) 50 in.^2
(4) 344 in.^2
The formula to find the surface area of a right rectangular prism is SA = 2lw + 2lh + 2wh, where l is the length, w is the width, and h is the height.
In this case, the dimensions of the textbook are given as 2 in x 14 in x 9 in. We can plug these values into the formula:
SA = 2(2)(14) + 2(2)(9) + 2(14)(9) = 56 + 36 + 252 = 344 in^2
Therefore, the correct answer is (4) 344 in.^2.
In this case, the dimensions of the textbook are given as 2 in x 14 in x 9 in. We can plug these values into the formula:
SA = 2(2)(14) + 2(2)(9) + 2(14)(9) = 56 + 36 + 252 = 344 in^2
Therefore, the correct answer is (4) 344 in.^2.
Sue is wrapping books to give as gifts. Book A has a length of 6.5 inches, a width of 1 inch, and a height of 8.5 inches. Book B has a length of 5.5 inches, a width of 2 inches, and a height of 8 inches. Based on surface area, which book will require less wrapping paper?(1 point)
(1) Book B will require less wrapping paper because its surface area is 0.5 in.^2 less than the surface area of Book A.
(2) Book B will require less wrapping paper because its surface area is 1.5 in. 2 less than the surface area of Book A.
(3) Book A will require less wrapping paper because its surface area is 1.5 in. 2 less than the surface area of Book B.
(4) Book A will require less wrapping paper because its surface area is 32.75 in. 2 less than the surface area of Book B.
(1) Book B will require less wrapping paper because its surface area is 0.5 in.^2 less than the surface area of Book A.
(2) Book B will require less wrapping paper because its surface area is 1.5 in. 2 less than the surface area of Book A.
(3) Book A will require less wrapping paper because its surface area is 1.5 in. 2 less than the surface area of Book B.
(4) Book A will require less wrapping paper because its surface area is 32.75 in. 2 less than the surface area of Book B.
To find the surface area of a book, we can use the formula SA = 2lw + 2lh + 2wh, where l is the length, w is the width, and h is the height.
For Book A:
SA = 2(6.5)(1) + 2(6.5)(8.5) + 2(1)(8.5) = 13 + 221 + 17 = 251 in^2
For Book B:
SA = 2(5.5)(2) + 2(5.5)(8) + 2(2)(8) = 22 + 88 + 32 = 142 in^2
Therefore, Book B will require less wrapping paper because its surface area is smaller than the surface area of Book A.
The correct answer is (2) Book B will require less wrapping paper because its surface area is 1.5 in^2 less than the surface area of Book A.
For Book A:
SA = 2(6.5)(1) + 2(6.5)(8.5) + 2(1)(8.5) = 13 + 221 + 17 = 251 in^2
For Book B:
SA = 2(5.5)(2) + 2(5.5)(8) + 2(2)(8) = 22 + 88 + 32 = 142 in^2
Therefore, Book B will require less wrapping paper because its surface area is smaller than the surface area of Book A.
The correct answer is (2) Book B will require less wrapping paper because its surface area is 1.5 in^2 less than the surface area of Book A.
1 answer