To find the volume of a basketball using the formula for the volume of a sphere, we can use the formula:
\[ V = \frac{4}{3} \pi r^3 \]
where \( V \) is the volume and \( r \) is the radius of the sphere.
- First, we need to find the radius of the basketball. The diameter of the basketball is 9 inches, so the radius \( r \) is half of the diameter:
\[ r = \frac{9 \text{ in}}{2} = 4.5 \text{ in} \]
- Now we can plug the radius into the volume formula. Using \( \pi \approx 3.14 \):
\[ V = \frac{4}{3} \cdot 3.14 \cdot (4.5)^3 \]
- First, calculate \( (4.5)^3 \):
\[ (4.5)^3 = 4.5 \times 4.5 \times 4.5 = 20.25 \times 4.5 = 91.125 \]
- Now substitute \( (4.5)^3 \) back into the volume formula:
\[ V = \frac{4}{3} \cdot 3.14 \cdot 91.125 \]
- Calculate \( \frac{4}{3} \cdot 3.14 \):
\[ \frac{4 \cdot 3.14}{3} \approx \frac{12.56}{3} \approx 4.18667 \]
- Now multiply this value by 91.125:
\[ V \approx 4.18667 \cdot 91.125 \approx 381.5 \]
Thus, the volume of the basketball is approximately:
\[ \boxed{381.5 \text{ in}^3} \]
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