The formula for the volume of a sphere is V = (4/3)πr^3, where r is the radius of the sphere. Since the basketball has a diameter of 9.2 inches, the radius is half of the diameter, which is 4.6 inches.
Plugging in the radius into the formula, we get:
V = (4/3)(3.14)(4.6)^3
V = (4/3)(3.14)(97.336)
V = 413.958 cubic inches
Therefore, the volume of the basketball is approximately 413.96 cubic inches.
Use the formula for the volume of a sphere to find the volume of a basketball that has a diameter of 9.2 inches. Use 3.14 as an approximation for pi and round your answer to the nearest hundredth, if necessary.
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incorrect
I apologize for the mistake. Let me correct it:
The radius of the basketball is half of the diameter, which is 9.2 / 2 = 4.6 inches.
Plugging the radius into the formula for the volume of a sphere, we get:
V = (4/3)π(4.6)^3
V = (4/3)(3.14)(97.336)
V = 4.1867 * 97.336
V = 407.08 cubic inches
Therefore, the volume of the basketball is approximately 407.08 cubic inches.
The radius of the basketball is half of the diameter, which is 9.2 / 2 = 4.6 inches.
Plugging the radius into the formula for the volume of a sphere, we get:
V = (4/3)π(4.6)^3
V = (4/3)(3.14)(97.336)
V = 4.1867 * 97.336
V = 407.08 cubic inches
Therefore, the volume of the basketball is approximately 407.08 cubic inches.
also incorrect. there's something in your answer that you don't need to consider
I apologize for the oversight. Let's correct it.
The formula for the volume of a sphere is V = (4/3)πr^3, where r is the radius of the sphere. Given that the basketball has a diameter of 9.2 inches, the radius, which is half the diameter, would be 4.6 inches.
Plugging the radius into the formula, we get:
V = (4/3) * 3.14 * (4.6)^3
V = (4/3) * 3.14 * 97.336
V = (4/3) * 305.5976
V = 407.4635 cubic inches
Rounding to the nearest hundredth, the volume of the basketball is approximately 407.46 cubic inches. Thank you for pointing out the error, and I appreciate your patience.
The formula for the volume of a sphere is V = (4/3)πr^3, where r is the radius of the sphere. Given that the basketball has a diameter of 9.2 inches, the radius, which is half the diameter, would be 4.6 inches.
Plugging the radius into the formula, we get:
V = (4/3) * 3.14 * (4.6)^3
V = (4/3) * 3.14 * 97.336
V = (4/3) * 305.5976
V = 407.4635 cubic inches
Rounding to the nearest hundredth, the volume of the basketball is approximately 407.46 cubic inches. Thank you for pointing out the error, and I appreciate your patience.