The formula for the surface area of a square pyramid is given by:
SA = base area + (0.5 * perimeter * slant height)
In this case, the base is square, so the base area is found by squaring the length of one side of the base:
base area = (side length)^2 = (40 in)^2 = 1600 in^2
We are given that the surface area (SA) is 2800 in^2.
Since the base length is 40 in, the perimeter of the base is 4 times the base length:
perimeter = 4 * 40 in = 160 in
Now we can substitute the known values into the formula and solve for the slant height:
2800 in^2 = 1600 in^2 + (0.5 * 160 in * slant height)
2800 in^2 - 1600 in^2 = 80 in * slant height
1200 in^2 = 80 in * slant height
Dividing both sides by 80 in:
15 in^2 = slant height
Therefore, the slant height of the square pyramid is 15 inches.
Use the formula for the surface area of a square pyramid to solve for the slant height if the length of the base is 40 in. and SA equals 2,800 in2
5 answers
What is the formula for finding the surface area of a regular triangular pyramid?(1 point)
Responses
SA=lw+12w4h2+l2−−−−−−−√+12l4h2+w2−−−−−−−√
cap s cap A is equal to l w plus 1 half w square root of 4 h squared plus l squared end root plus 1 half l square root of 4 h squared plus w squared end root
SA=2(wl+lh+hw)
cap s cap A is equal to 2 times open paren w l plus l h plus h w close paren
SA=12ab+3(12lb)
cap s cap A is equal to 1 half A b plus 3 times open paren 1 half pounds close paren
SA=a2+2aa24+h2−−−−−−√
Responses
SA=lw+12w4h2+l2−−−−−−−√+12l4h2+w2−−−−−−−√
cap s cap A is equal to l w plus 1 half w square root of 4 h squared plus l squared end root plus 1 half l square root of 4 h squared plus w squared end root
SA=2(wl+lh+hw)
cap s cap A is equal to 2 times open paren w l plus l h plus h w close paren
SA=12ab+3(12lb)
cap s cap A is equal to 1 half A b plus 3 times open paren 1 half pounds close paren
SA=a2+2aa24+h2−−−−−−√
SA = a^2 + 2a * √(a^2/4 + h^2)
The formula for finding the surface area of a regular triangular pyramid is SA = a^2 + 2a * √(a^2/4 + h^2)
The formula for finding the surface area of a regular triangular pyramid is SA = a^2 + 2a * √(a^2/4 + h^2)
1. 72.52
2. 382.59
3. 500
4. 15
5. SA=12ab+3(12lb)
2. 382.59
3. 500
4. 15
5. SA=12ab+3(12lb)
To determine the surface area of a regular triangular pyramid using the formula SA = 1/2ab + 3(1/2lb), we need to have the values of a (triangle base length), b (triangle height), and l (slant height).
Unfortunately, you have not provided the necessary values to compute the surface area using this formula. Please provide the missing values in order to proceed with the calculation.
Unfortunately, you have not provided the necessary values to compute the surface area using this formula. Please provide the missing values in order to proceed with the calculation.
1 answer