To factor the polynomial \( f(x) = 4x^3 - 8x^2 - 9x + 18 \) by grouping, we proceed as follows:
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Factor by Grouping:
- Group the terms: \( (4x^3 - 8x^2) + (-9x + 18) \)
- Factor out the common factors from each group:
- From \( 4x^3 - 8x^2 \), we can factor out \( 4x^2 \): \[ 4x^2(x - 2) \]
- From \( -9x + 18 \), we can factor out \( -9 \): \[ -9(x - 2) \]
- We can now factor out the common binomial \( x - 2 \): \[ f(x) = (x - 2)(4x^2 - 9) \]
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Factor the Quadratic:
- The quadratic \( 4x^2 - 9 \) is a difference of squares: \[ 4x^2 - 9 = (2x - 3)(2x + 3) \]
- Therefore, the complete factorization of the polynomial is: \[ f(x) = (x - 2)(2x - 3)(2x + 3) \]
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Find the Zeros:
- Set \( f(x) = 0 \): \[ (x - 2)(2x - 3)(2x + 3) = 0 \]
- The zeros are:
- \( x - 2 = 0 \) ⇒ \( x = 2 \)
- \( 2x - 3 = 0 \) ⇒ \( x = \frac{3}{2} = 1.5 \)
- \( 2x + 3 = 0 \) ⇒ \( x = -\frac{3}{2} = -1.5 \)
- Thus, the zeros are \( x = 2, 1.5, -1.5 \).
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Graphing Information:
- The graph has zeros at \( x = 2, 1.5, -1.5 \), represented as dots on the x-axis at these points.
- For end behavior:
- The leading coefficient (4) is positive, and the degree of the polynomial is odd (3), so the curve falls on the left and rises on the right.
- The relative maximum is at approximately \( (-0.5, 20) \), and the relative minimum is at approximately \( (1.75, -1) \).
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Domain and Range:
- The domain of the function is: \[ (-\infty, \infty) \]
- The range is also: \[ (-\infty, \infty) \] (The polynomial can take all y values since it is cubic and unbounded).
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Intervals for Positivity and Negativity:
- The curve is negative between the zeros, specifically:
- From \( -1.5 \) to \( 1.5 \) (negative between the first zero -1.5 and second zero 1.5) and also from \( -\infty \) to \( -1.5 \).
- Positive intervals are:
- From \( (-\infty, -1.5) \) (down to -1.5) and from \( (1.5, 2) \) (coming back up to 2).
- The curve is negative between the zeros, specifically:
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Intervals for Increasing and Decreasing:
- The curve is rising:
- From \( (-\infty, -1.5) \) and from \( (1.5, 2) \).
- The curve is falling:
- From \( (-1.5, 1.5) \).
- The curve is rising:
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Average Rates of Change:
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To find the average rate of change over the intervals: \(-2\) to \(0\): \[ \text{Average Rate of Change} = \frac{f(0) - f(-2)}{0 - (-2)} = \frac{18 - (f(-2))}{2} \] where \( f(-2) = 4(-2)^3 - 8(-2)^2 - 9(-2) + 18 = -32 - 32 + 18 + 18 = -28 \). Thus: \[ \text{Average Rate of Change} = \frac{18 - (-28)}{2} = \frac{46}{2} = 23 \]
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Over the interval \([-3, 4]\): \[ \text{Average Rate of Change} = \frac{f(4) - f(-3)}{4 - (-3)} = \frac{f(4) - f(-3)}{7} \] Calculate \( f(4) = 4(4^3) - 8(4^2) - 9(4) + 18 = 64 - 128 - 36 + 18 = -82 \) and \( f(-3) = -28 \). Thus: \[ \text{Average Rate of Change} = \frac{-82 - (-28)}{7} = \frac{-82 + 28}{7} = \frac{-54}{7} \approx -7.71 \]
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Summary:
- Zeros: \( x = 2, 1.5, -1.5 \)
- Domain: \( (-\infty, \infty) \)
- Range: \( (-\infty, \infty) \)
- Negative Intervals: From \( -1.5 \) to \( 1.5 \)
- Positive Intervals: From \( (-\infty, -1.5) \) and from \( (1.5, 2) \)
- Rising Intervals: From \( (-\infty, -1.5) \) and \( (1.5, 2) \)
- Falling Intervals: From \( (-1.5, 1.5) \)
- Average Rate of Change:
- Over \( [-2, 0] = 23 \)
- Over \( [-3, 4] \approx -7.71 \)
You can verify the curve by graphing it using a graphing calculator and comparing it with your drawn graph.