To solve this problem, we need to first calculate the number of moles of hydrogen in 14g of H₂:
Molar mass of H₂ = 2.0 g/mol
Number of moles of H₂ = Mass / Molar mass = 14g / 2.0 g/mol = 7 mol
Now, we can use the stoichiometry of the reaction to determine the number of moles of ammonia produced when 7 moles of hydrogen react:
From the balanced equation:
N₂ + 3H₂ → 2NH₃
For every 3 moles of H₂ reacting, 2 moles of NH₃ are produced.
Number of moles of NH₃ = (7 mol H₂) x (2 mol NH₃ / 3 mol H₂) = 4.67 mol NH₃
Finally, we can convert the number of moles of ammonia to grams:
Molar mass of NH₃ = 14.0 g/mol
Mass of NH₃ = (4.67 mol) x (14.0 g/mol) = 65.4 g
Therefore, if 14g of H₂ are reacted, 65.4g of NH₃ are produced.
Use the following reaction. Remember to first check if it is balanced!
N2+3H22NH3
nitrogen + hydrogen ammonia
Complete the stoichiometry table below to calculate how many grams of ammonia are produced if 14g of H₂ are reacted with an excess of N₂. You will need to calculate molar masses with the following information:
Substance H N
Molar mass 1.0 g/mol 14.0 g/mol
14 g H₂ 2 1 mol H2 _____ __ g NH3
1.0 g H₂ _______ 1 mol NH3
1 answer