use the following instructions for problems 1 and 2: for a right triangle with legs a and b and hypotenuse c, find the missing side length. round your answer to the nearest tenth, if necessary.
1. a = 5;b = 10
- 3.9
-11.2
-8.7
-125
2. a = 9;c=15
-12
-17.5
-36
-6
3. which of the following side lengths will not make a right triangle?
-12,16,20
-5,12,13
-6,17,20
-3.5,12,12.5
4. find the length of a segment with endpoints at ( -1, -3 ) and ( 6, 0 ). round your answer to the nearest tenth, if necessary.
-10
-5.8
-6
-7.6
5. find the midpoint of a segment with endpoints at ( 7, 9 ) and ( -1, -1 ).
- ( 4, 5 )
- (2,0 )
- ( 3, 4 )
- ( 8, -1 )
6. find the slope of the line that passes through ( -2, 1 ) and (1, 10 )
- 3
- -3
- 1/3
- -1/3
7. which equation represents a direct variation?
- 3y=2x + 1;1
- y = -5x - 11;5
- 4y = -12x;-3
- y+7 = 2x - 1;7
8. suppose y varies directly with x, and y = 12 when x = -3. what is the value of y when x=6?
- -24 *****
- 2
- -2
- -4
9. what is the equation of a line with a slope of -7 and a y-intercept of 6?
- 6y = -7x
- y = 6x + ( -7 )
- -7y = x + 6
- y = -7x + 6
10. what is the equation of the line that passes through the points ( 0, 4 ) and ( 3, -2 )
- y = 2x + 0
- y = - 1/2x + ( -2 )
- y = -2x + 4
- y = 1/2x + 4
11. what is the equation of the line through ( 5, 1 ) with a slope of -3?
- y + 1 = 3 ( x + 5 )
- y - 1 = 3 ( x - 5 )
- y - 1 = -3 ( x - 5 )
- y + 1 = -3 ( x - 5 )
can someone help?
3 answers
#1 c^2 = 5^2+10^2 = 125
c = 11.2
#2 9^2 + b^2 = 15^2
b = 12
#3 6,17,20
6^2 + 17^2 = 36+289 = 325
20^2 = 400
#4 the length is just the hypotenuse of a right triangle with legs 3 and 7: 7.6
#5 the midpoint has coordinates halfway from one end to the other: (3,4)
#6 slope is (10-1)/(1-(-2)) = 9/3 = 3
#7 direct variation means y=kx
There can be no other constants involved. So, -4y=-12x
#8 correct
#9 the slope-intercept form isn't called that for nothing!!
y = -7x+6
#10 the slope is -2, so
y-4 = -2(x-0)
or, y = -2x+4
#11 even easier:
y-1 = -3(x-5)
However, my helping you with these problems does not alleviate your evident need to do lots more of these on your own!