To solve this problem, we can use the combined gas law, which states that the ratios of pressure, volume, and temperature for a gas are equal. The formula is:
(P1 * V1) / T1 = (P2 * V2) / T2
Where:
P1 = initial pressure (2.0 atm)
V1 = initial volume (30. L)
T1 = initial temperature (27°C + 273.15 = 300.15 K)
P2 = final pressure (2.0 atm)
V2 = final volume (unknown)
T2 = final temperature (54°C + 273.15 = 327.15 K)
Plugging in the values into the formula:
(2.0 atm * 30. L) / 300.15 K = (2.0 atm * V2) / 327.15 K
Simplifying the equation:
60.0 L/atm = 2.0 V2/atm
Dividing both sides by 2.0 atm:
V2 = 60.0 L / 2.0
V2 = 30.0 L
Therefore, the volume of the gas when the temperature is raised to 54°C is 30.0 L.
Use the following information to answer the next questions:
A gas occupies 30. L at 2.0 atm pressure and 27°C.
Calculate its volume if the pressure remains at 2.0 atm, but the temperature is raised to 54°C.
1 answer
1 answer