To find the efficiency of energy transfer, we can use the provided formula:
\[ \text{Efficiency} = \left( \frac{\text{Energy level transferred to next level}}{\text{Total energy input}} \right) \times 100 \]
In this case:
- Energy level transferred to the polar bear = 375 Kcal (the energy the polar bear receives from the harbor seal).
- Total energy input from the harbor seal = 2500 Kcal (the energy content of the harbor seal).
Now, we can plug the numbers into the formula:
\[ \text{Efficiency} = \left( \frac{375 \text{ Kcal}}{2500 \text{ Kcal}} \right) \times 100 \]
Calculating this:
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Calculate the fraction: \[ \frac{375}{2500} = 0.15 \]
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Now multiply by 100 to get the percentage: \[ 0.15 \times 100 = 15% \]
Thus, the efficiency of energy transfer between the harbor seal and the polar bear is 15%.