Use the following formula to find the efficiency of energy transfer between the harbor seal (2,500 Kcal) and a polar bear (375 Kcal).

(Energy level transfered to next level)(Total energy input) × 100


(1 point)
Responses

10%
10%

12%
12%

20%
20%

15%

1 answer

To calculate the efficiency of energy transfer between the harbor seal and the polar bear using the formula provided, you would use the following values:

  • Energy level transferred to the next level (energy received by the polar bear): 375 Kcal
  • Total energy input (energy contained in the harbor seal): 2500 Kcal

Next, we can plug these values into the formula:

\[ \text{Efficiency} = \left( \frac{375 \text{ Kcal}}{2500 \text{ Kcal}} \right) \times 100 \]

Calculating the fraction:

\[ \frac{375}{2500} = 0.15 \]

Now, multiply by 100 to get the efficiency percentage:

\[ 0.15 \times 100 = 15% \]

Therefore, the efficiency of energy transfer between the harbor seal and the polar bear is 15%.