Use the FOIL method to multiply the binomials.

(x-7y)(7x+6y)

(x-7y)(7x+6y) = blank (Simplify your answer.)

1 answer

To multiply the binomials \((x-7y)(7x+6y)\) using the FOIL method, we follow these steps:

  1. First: Multiply the first terms of each binomial. \[ x \cdot 7x = 7x^2 \]

  2. Outer: Multiply the outer terms of the binomials. \[ x \cdot 6y = 6xy \]

  3. Inner: Multiply the inner terms of the binomials. \[ -7y \cdot 7x = -49xy \]

  4. Last: Multiply the last terms of each binomial. \[ -7y \cdot 6y = -42y^2 \]

Now, combine all these results: \[ 7x^2 + 6xy - 49xy - 42y^2 \]

Next, combine the like terms (\(6xy\) and \(-49xy\)): \[ 7x^2 + (6xy - 49xy) - 42y^2 = 7x^2 - 43xy - 42y^2 \]

Thus, the simplified result is: \[ \boxed{7x^2 - 43xy - 42y^2} \]