Use the figure to answer the question.

An illustration shows a right inclined transversal passing through two parallel lines labeled upper M and upper N. Four angles are formed at the intersections of the transversal with upper M and upper N. If M and N are parallel and angle 1 is 135°, what is the sum of angle 6 and angle 8?

1 answer

Given that angle 1 is 135° and the lines M and N are parallel, we can apply the properties of angles formed by a transversal cutting through parallel lines.

  1. Identify Angles:

    • Since angle 1 is 135°, and it is an exterior angle relative to the angles formed at the intersections, we can determine the corresponding interior angle created on line M which is adjacent to angle 1. Specifically,
    • Angle 2 (the corresponding angle on line M) would be supplementary to angle 1. Thus, angle 2 = 180° - 135° = 45°.
  2. Find Angle 6 and its Relation to Angle 2:

    • Angle 6 is vertical to angle 2, so angle 6 = angle 2 = 45°.
  3. Find Angle 8:

    • Since M and N are parallel lines, angle 8 (located on line N corresponding to angle 2) is equal to angle 2 due to corresponding angles.
    • Therefore, angle 8 = angle 2 = 45°.
  4. Calculate the Sum of Angles 6 and 8:

    • The sum of angle 6 and angle 8 is: \[ \text{Angle 6} + \text{Angle 8} = 45° + 45° = 90° \]

Thus, the sum of angle 6 and angle 8 is \( \boxed{90°} \).