Since M and N are parallel lines, angle 1 and angle 6 are corresponding angles and therefore congruent.
Therefore, angle 6 is also 135°.
Angle 8 is an alternate exterior angle to angle 6, which means they are congruent.
Therefore, angle 8 is also 135°.
The sum of angle 6 and angle 8 is 135° + 135° = 270°.
Use the figure to answer the question.
An illustration shows a right inclined transversal passing through two parallel lines labeled upper M and upper N. Four angles are formed at the intersections of the transversal with upper M and upper N. The angles formed around the intersection point of the transversal and upper M are labeled clockwise, starting from the upper left quadrant: 1, 2, 4, and 3. The corresponding angles formed around the intersection point of upper N are labeled clockwise, starting from the upper left quadrant: 5, 6, 8, and 7.
If M and N are parallel and angle 1 is 135° , what is the sum of angle 6 and angle 8?
(1 point)
$$
Skip to navigation
1 answer
5 answers