Use the figure to answer the question.

Question

An illustration shows a right inclined transversal passing through two parallel lines labeled upper M and upper N. Four angles are formed at the intersections of the transversal with upper M and upper N. The angles formed around the intersection point of the transversal and upper M are labeled clockwise, starting from the upper left quadrant: 1, 2, 4, and 3. The corresponding angles formed around the intersection point of upper N are labeled clockwise, starting from the upper left quadrant: 5, 6, 8, and 7.

If M and N are parallel and angle 1 is 135° , what is the sum of angle 6 and angle 8?

Answer 1

Since line M is parallel to line N, angles 1 and 6 are corresponding angles. Corresponding angles are congruent when lines are parallel, so angle 6 is also 135°.

Similarly, angle 4 and angle 7 are corresponding angles, and since angle 4 is 135°, angle 7 is also 135°.

The sum of angle 6 and angle 8 is 135° + 135° = 270°. Answer: \boxed{270}.

Answer 2

2 and 8 are 40 4 and 7 are 135 so whats the answer because 270 is not it

Answer 3

Apologies for the mistake in the previous response. Let's reconsider the problem:

From the given information, we know that angle 1 is 135°.

Since angles 1 and 5 are corresponding angles, we can conclude that angle 5 is also 135°.

Angles 5 and 6 are vertically opposite angles, which means they are congruent. Therefore, angle 6 is also 135°.

Similarly, angles 4 and 8 are corresponding angles. Since angle 4 is 40°, we can conclude that angle 8 is also 40°.

The sum of angle 6 and angle 8 is 135° + 40° = 175°.

Therefore, the correct answer is \boxed{175}.