First, we need to find the factor of the equation g(x) = x^3 - 3x^2 - 10x + 24 by synthetic division.
-3 | 1 -3 -10 24
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1 -6 8 0
The remainder is 0, which means -3 is a zero of g(x). Therefore, (x+3) is a factor of g(x).
To find the other factor, we divide the polynomial obtained from synthetic division (1x^2 - 6x + 8) by using the factored form (x+3).
x-3
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x+3 | 1 -6 8
-(1 -3 9)
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-3 17
Therefore, the factorization of g(x) = x^3 - 3x^2 - 10x + 24 is (x+3)(x^2 - 3x + 8).
Use the Factor Theorem to factor g(x)=x3−3x2−10x+24
into a product of linear factors, given that −3
is a zero of g(x)
.(1 point)
g(x)=
1 answer
1 answer